First we have to convert the equation to standard form to find its center and radius.
[tex] x^{2} -10x+ y^{2}-10y=-25 \\ \\
x^{2} -2(x)(5)+25 +y^{2}-2(y)(5)+25=-25+50 \\ \\
(x-5)^{2}+(y-5)^{2}=25 [/tex]
So, the center of the circle is (5,5) with radius equal to 5.
So, Draw the circle placing the center at (5,5) and with radius equal to 5.
