The balance chemical equation for this reaction is as follow,
2 Na + Br₂ -------> 2 NaBr
According to this equation, 45.98 g when reacted with excess of Bromine produces 205.78 g of NaBr.
Now, Calculating for 5 g fo Na metal,
= (205.78 × 5) ÷ 45.98
= 22.37 g of NaBr
