1. Fill in the x-coordinate in the function [tex]y = 2 \times 3 - 4[/tex] [tex]y = 6 - 4[/tex] [tex]y = 2[/tex] We find that the y-coordinate is 2. So this point is on the graph.
2. Same work [tex]y = \frac{1}{4} \times 4 + 15[/tex] [tex]y = 1 + 15[/tex] [tex]y = 16[/tex] We find that the y-coordinate is 16. So this point isn't on the graph.
