I drew the image that this problem gave me. Based on that image, I solved the required measurement using the sin theta formula:
sin θ = opposite / hypotenuse
On my drawing, I made an imaginary right triangle to solve for the distance.
Pls. see my attachment.
Sin θ =
opposite / hypotenuse
Sin(30) =
opposite / 48m
Sin (30) *
48m = opposite
24m =
opposite
Sin(30) =
opposite / 45 m
Sin(30) * 45
m = opposite
22.5 m =
opposite
24m + 22.5m
= 46.5 m
I am 46.5m away from my original starting point.
