Respuesta :
[tex]\bf R=log(x)\implies R=log_{10}(x)\qquad \boxed{R=4.1}\qquad 4.1=log_{10}(x)\\\\
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\textit{Logarithm Cancellation Rules}\\\\
log_{{ a}}{{ a}}^x\implies x\qquad \qquad
\boxed{{{ a}}^{log_{{ a}}x}=x}\\\\
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thus\qquad 10^{4.1}=10^{log_{10}(x)}\implies 10^{4.1}=x[/tex]
Answer:
12589.25
Step-by-step explanation:
this is correct on plato
