Respuesta :

Let the side of the square = a units,   the area of the square = a^2 sq units

Area of the 4 semicircles  = area of 2 circles = 2 pi r^2 =  2pi (1/2 a)^2
  =   pi a^2 / 2

Probability of a point in the unshaded square being picked)  = area square / area of the total figure  = a^2  / (a^2 * pi/2)   = 1 / pi/2 = 2 /pi

which is approximately  65%

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