Answer: [tex]2y-3x=0[/tex]
Step-by-step explanation:
We know that the equation of a line with points (a,b) and (c,d) is given by :_
[tex](y-b)=\frac{d-b}{c-a}(x-a)[/tex]
The points on the given line are (0,0) and (-2,-3).
Then the equation of the given line will be :_
[tex](y-0)=\frac{-3-0}{-2-0}(x-0)\\\\\Rightarrow y=\frac{3}{2}x\\\\\Rightarrow2y-3x=0[/tex]
Hence, the equation of the given line in picture is [tex]2y-3x=0[/tex]
