Answer:
Option B is correct
[tex]x-3 = \pm \sqrt{7}[/tex]
Step-by-step explanation:
Given the equation:
[tex](x-3)^2 = 7[/tex]
taking square root both sides we have;
[tex]\sqrt{(x-3)^2} = \pm \sqrt{7}[/tex]
Using exponent rules:
[tex]\sqrt[n]{x^n}=x[/tex]
then;
[tex]x-3 = \pm \sqrt{7}[/tex]
Therefore, the following statements follows from [tex](x-3)^2 = 7[/tex] is, [tex]x-3 = \pm \sqrt{7}[/tex]
