Given the function
[tex]p(t)=800(1.039)^t[/tex]
t= number of years from today
The current price (t=0) is
[tex]p(0)=800(1.039)^0[/tex][tex]p(0)=800*1[/tex][tex]p(0)=800[/tex]
Current price= 800
Price 10 years from today (t=10)
[tex]p(10)=800(1.039)^{10}[/tex][tex]p(10)=1172.85[/tex]
rounded to the nearest dollar the price in 10 years from today
p(10) = 1173
