Step 1: Write out the equation
[tex]8(j-4)=2(4j-16)[/tex]Step 2: Divide both sides by 2
[tex]\begin{gathered} \frac{8(j-4)}{2}=\frac{2(4j-16)}{2} \\ \text{Therefore} \\ 4(j-4)=4j-16 \end{gathered}[/tex]Step 3: Expand the left side of the equation to get
[tex]\begin{gathered} 4j-16=4j-16 \\ \text{Thus} \\ 4j-4j=-16+16 \\ 0=0 \end{gathered}[/tex]0 = 0 is always true no matter the value of j.
Hence, the number of solutions is infinite
