The given is a triangle. As we know that the sum of all the interior angles in a triangle is 180 degrees, we have,
[tex]\begin{gathered} 6x-5+x+8+2x-3=180 \\ 9x=180 \\ x=\frac{180}{9}=20 \end{gathered}[/tex]
Therefore, the angles can be calculated as,
[tex]\begin{gathered} K=6\times20-5=115 \\ J=20+8=28 \\ L=2\times20-3=37 \end{gathered}[/tex]
