Answer:
[tex]V=14^5[/tex]
Explanation:
Given the logarithmic equation:
[tex]\log_{14}(V)=5[/tex]
The relationship between the logarithm and exponential forms is given below:
[tex]\log_ba=c\implies b^c=a[/tex]
That is:
• The base (b) in the logarithmic form becomes the base of the exponent.
,
• The answer (c) in the logarithmic form becomes the exponential form.
Thus, the given equation in exponential equation is:
[tex]V=14^5[/tex]
