Given
[tex]9^{\frac{2}{3}}[/tex]
To write it in the simplest form and to find which value remains under the radical.
Explanation:
It is given that,
[tex]9^{\frac{2}{3}}[/tex]
It is known that,
[tex]x^{\frac{m}{n}}=\sqrt[n]{x^m}[/tex]
That implies,
[tex]\begin{gathered} 9^{\frac{2}{3}}=\sqrt[3]{9^2} \\ =\sqrt[3]{3\times3\times3\times3} \\ =3\sqrt[3]{3} \end{gathered}[/tex]
Therefore, the simplest form of the expression is,
[tex]3\sqrt[3]{3}[/tex]
and the value that remains under the radical is 3.
