slope of intercept from the equation of line is
[tex]\begin{gathered} y=mx+c \\ \text{where c is the intercept part of y} \\ c=1 \\ l\in e\text{ cuts y-a}\xi s\text{ at 1} \\ so\text{ point (0,1)} \\ and\text{ cut on 2nd place at 3 on x-a}\xi s \\ so\text{ point is (3,0)} \\ slope(m)=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{0-1}{3-0} \\ m=-\frac{1}{3} \\ \text{equation of line is} \\ y=-\frac{1}{3}x+1 \end{gathered}[/tex]