Explanation:
We are given: 2.90mol of ideal gas
At STP: Pressure = 1 atm
: Temperature = 273.15 K
: R = 0.08205 L.atm/mol.K
Using the ideal gas law:
[tex]\begin{gathered} PV\text{ = nRT} \\ \\ \therefore V\text{ = }\frac{nRT}{P}\text{ = }\frac{2.9\text{ }\times0.08205\times273.15}{1}\text{ = 64.99 L} \end{gathered}[/tex]Answer:
V = 64.99 L
