Given
Amount of water,
[tex]m=20\text{ ml}[/tex]
Temperature is,
[tex]T=0.00C[/tex]
To find:
Energy required to freeze the water.
Explanation:
The latent heat of fusion is
[tex]L=33.5\times10^4\text{ J/}kg[/tex]
Converting the amount of water to kg,
[tex]m=0.020kg[/tex]
Thus the energy required is:
[tex]\begin{gathered} H=mL \\ \Rightarrow H=0.020\times33.5\times10^4=0.67\times10^4J \end{gathered}[/tex]
Conclusion:
The amount of energy required is
[tex]0.67\times10^4J[/tex]
