The Sine rule formula is,
[tex]\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}[/tex]
Given:
[tex]\begin{gathered} a=13.9in \\ A=83^0 \\ b=18.3in \\ B=? \end{gathered}[/tex]
Let us solve for solve for the measure of angle B
[tex]\frac{13.9}{sin83^0}=\frac{18.3}{sinB}[/tex]
Therefore,
[tex]\begin{gathered} sinB=\frac{18.3\times sin83^0}{13.9}=1.30673342266 \\ \therefore B=sin^{-1}(1.30673342266)=No\text{ solution} \end{gathered}[/tex]
Hence, there are no possible solutions for this triangle (OPTION C).
