Equation
[tex]\frac{2x^3-4x^2-3x}{2x}[/tex]
To operate this fraction we will separate the numerator and divide each term with the denominator.
[tex]\begin{gathered} \frac{2x^3}{2x}-\frac{4x^2}{2x}-\frac{3x}{2x} \\ x^2-2x-\frac{3}{2} \end{gathered}[/tex]The answer would be
[tex]x^2-2x-\frac{3}{2}[/tex]