ANSWER:
250500 J
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 750 grams
We can determine the amount of heat removed by taking into account the following image:
This means that to go from water to ice there is an absorbed radiation dose of 334 J/g, therefore, the heat removed is:
[tex]\begin{gathered} Q=m\cdot a \\ \\ \text{ We replacing:} \\ \\ Q=750\cdot334 \\ \\ Q=250500\text{ J} \end{gathered}[/tex]
The heat removed is 250500 joules.
