Given that, the triangle is a right angled triangle. Therefore,
[tex]\text{hypotenuse}^2=base^2+altitude^2[/tex]
Given that, hypotenuse is 10, altitude is 5 and base is x. Thus,
[tex]\begin{gathered} 10^2=x^2+5^2 \\ x^2=100-25 \\ x^2=75 \\ x=5\sqrt[]{3} \end{gathered}[/tex]
Hence, Option D.
