SOLUTION
The probability is a binomial probability
The probability is given as
[tex]\text{nCxp}^xq^{n-x}[/tex]
Where p= proability of succes=0.3
q=probability of failure=1-p=1-0.3=0.7
n=10, x=7
Then, substitute the parameters into the formula
[tex]10C_7(0.3)^7(0.7)^3[/tex][tex]\begin{gathered} 10C_7=120 \\ 120\times2.187\times10^{-4}\times0.343 \end{gathered}[/tex]
Then we have
[tex]\begin{gathered} 9.0017\times10^{-3} \\ 0.0090017 \end{gathered}[/tex]
The probability of x-success is 0.009
