Given:
Rectangle ABCD is similar to rectangle JKLM
From the first rectangle, we have:
AB = 15
DC = 6
From the second rectangle, we have:
JM = 10
ML = 5
We know that,
AD ~ JM
DC ~ ML
Thus, we have the ratio as:
[tex]\frac{AD}{JM}=\frac{DC}{ML}[/tex][tex]\begin{gathered} \frac{AD}{JM}=\frac{15}{10}=\frac{3}{2} \\ \end{gathered}[/tex]
Therefore the ratio of AD to JM is:
[tex]\frac{3}{2}[/tex]
ANSWER:
[tex]C\text{. }\frac{3}{2}[/tex]
