Answer:
1.15052
Explanation:
Given that:
Mean exam score = 84.28, that is,
[tex]\mu=84.28[/tex]
Standard deviation = 6.71, that is,
[tex]\sigma=6.71[/tex]
Score got on exam, x = 92.
The formula to find z-score is
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Plug in the given values into the formula.
[tex]\begin{gathered} z=\frac{92-84.28}{6.71} \\ =1.15052 \end{gathered}[/tex]
Thus, the required z-score is 1.15052.
