Answer:
[tex]\frac{b+3}{2}[/tex]
Explanation:
Given the below expression;
[tex]\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}[/tex]
Let's go ahead and simplify the expression as shown below;
[tex]\frac{b-5}{2b}\times\frac{b(b+3)}{b-5}=\frac{b(b+3)}{2b}=\frac{b+3}{2}[/tex]
