We have two similar triangles.
They will have proportional sides and equal measures.
Then, if we have to evaluate Then, we can write:
[tex]\begin{gathered} m\angle A=m\angle D \\ 3x+18=4x+2 \\ 3x-4x=2-18 \\ -x=-16 \\ x=16 \end{gathered}[/tex]
Knowing x, we can calculate m[tex]\begin{gathered} m\angle A=3x+18 \\ m\angle A=3\cdot16+18=48+18=66\degree \end{gathered}[/tex]Answer: the measure of A is 66º
