We have the following:
[tex]\begin{gathered} AB=AC+CB \\ AC=2x+5 \\ AB=27x \\ CB=5x+15 \end{gathered}[/tex]
replacing:
[tex]\begin{gathered} 27x=2x+5+5x+15 \\ 27x-2x-5x=20 \\ 20x=20 \\ x=\frac{20}{20} \\ x=1 \end{gathered}[/tex]
Therefore:
[tex]\begin{gathered} AC=2\cdot1+5=7 \\ AB=27\cdot1=27 \\ CB=5\cdot1+15=20 \end{gathered}[/tex]
x = 1
AC = 7
AB = 27
CB = 20
