The function f(x)=x²-12x + 3 is a quadratic function, the vertex is given as x = -b/2a
f(x)=x²-12x + 3
a = 1, b=-12, c=3
x = -(-12)/2(1)
x = 12/2
x = 6
to get the y-coordinate, substitute x = 6 into f(x)
f(6) = 6²-12(6) + 3
= 36-72+3
=-33
the coordinate of the vertex is (6, -33)
