a For any relation to be a function, an independent variable x cannot produce different dependent varible y
From the table,
when x = 5, y = 2
Also, when x = 5, y = 5
and when x = 5, y = 7
We can see that x= 5 produces 3 different values of y ( that is 2, 5, and 7). This has disobeyed the rule of a function
Hence, the table is not a function
The answer is False
