9ab5 - 6ab4 = 3 . 3 . a . b . 5 - 3 . 2 . a . b . 4
Now we can look for the common factors: 3 , a, and b. Then we put these factors in evidence:
[tex]3ab(\frac{9ab5}{3ab}-\frac{6ab4}{3ab})=3ab(3\cdot5-2\cdot4)=3ab(15-8)=3ab7[/tex]Therefore, the complete factored form of this polynomial is 3ab7.
