Solution:
The area of a trapezoid is expressed as
[tex]A=\frac{(b_1+b_2)}{2}\times h[/tex]
Given the trapezoid below:
where
[tex]\begin{gathered} b_1=6 \\ b_2=11 \\ h=8 \end{gathered}[/tex]
By substitution, we have
[tex]\begin{gathered} Area=\frac{(6+11)}{2}\times8 \\ =\frac{17}{2}\times8 \\ =68\text{ square centimeters} \end{gathered}[/tex]
Hence, the area of the trapezoid is
[tex]68\text{ square centimeters}[/tex]
