To find the equation of a line we can use the following:
[tex]y-y_1=m(x-x_1)[/tex]Where m is the slope of the line and (x1, y1) is a point of the line.
Then, replacing m by -2/3 and (x1, y1) by (-1, 3), we get:
[tex]\begin{gathered} y-3=-\frac{2}{3}(x-(-1)) \\ y-3=-\frac{2}{3}(x+1) \\ y-3=-\frac{2}{3}x-\frac{2}{3}\cdot1 \\ y=-\frac{2}{3}x-\frac{2}{3}+3 \\ y=-\frac{2}{3}x+\frac{7}{3} \end{gathered}[/tex]Answer: y = (-2/3)x + (7/3)
