Since the radius SR is perpendicular to the chord LK, it divides the chord in two segments with equal length, so we can find PL:
[tex]\begin{gathered} LK=2\cdot PL \\ 2\cdot PL=12 \\ PL=6 \end{gathered}[/tex]
Since SN and SP have the same length, the chords LK and JK also have the same length, so:
[tex]\begin{gathered} JK=LK \\ 2x-2=12 \\ 2x=14 \\ x=7 \end{gathered}[/tex]
So the value of x is 7.
