Answer:
Step-by-step explanation:
The formula used to find the distance between the point and the plane is:
- [tex]D = | ax_0 + by_0 + cz_0 + d| /\sqrt{a^2+b^2+c^2}[/tex], where
ax + by + cz + d = 0 is the plane and (x₀, y₀, z₀) is the point.
It is obvious that:
- a = 1, b = - 1, c = 2 and d = - 6,
- x₀ = 4, y₀ = 2, z₀ = 1.
Substitute and calculate:
- [tex]D = | 1*4 - 1*2 + 2*1 - 6| /\sqrt{1^2+(-1)^2+2^2}=|-2|/\sqrt{6} =2/\sqrt{6}= 0.816[/tex]
