Answer:
B. [tex]f^{-1}(x) = \frac{x + 3}{9}[/tex]
Step-by-step explanation:
[tex]let \space\ y = f(x)\\\\y = 9x -3\\[/tex]
• Now make x the subject of the equation:
[tex]9x = y + 3\\\\x = \frac{y + 3}{9} \\[/tex]
• Replace x with f⁻¹(x) and y with x:
[tex]f^{-1}(x) = \frac{x + 3}{9}[/tex]
