The sine of ∠I is represented by the ratio 63:65
First, let's draw the triangle (see the picture below.)
We need to use it here.
-sin = opposite/hypotenuse
-cos = adjacent/hypotenuse
-tan = opposite/adjacent.
Assuming that ∠I is Ф,
we can see that its opposite side is equal to 63 and the hypotenuse is 65. Therefore,
[tex]sin(I)=\frac{63}{65} \\\\sinI=75^0[/tex]
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