Answer:
[tex]3m^2n[/tex]
Step-by-step explanation:
Since,
[tex]48m^5n=3\times 2\times 2\times 2\times 2\times m\times m\times m\times m\times m\times n[/tex]
[tex]81m^2n^2=3\times 3 \times 3\times 3\times m\times m\times n\times n[/tex]
Thus,
[tex]\text{GCF of }48m^5n\text{ and }81m^2n^2=3\times m\times m\times n[/tex]
[tex]=3m^2n[/tex]
