Answer:
[tex](x-5)^2+(y-1)^2=20[/tex]
Step-by-step explanation:
Equation of a circle
[tex](x-a)^2+(y-b)^2=r^2[/tex]
(where (a, b) is the center and r is the radius)
Given:
- center = (5, 1)
- diameter = 4√5
Diameter = 2r (where r is the radius)
⇒ r = 4√5 ÷ 2 = 2√5
Substituting these values into the equation:
[tex]\implies (x-5)^2+(y-1)^2=(2\sqrt{5})^2[/tex]
[tex]\implies (x-5)^2+(y-1)^2=20[/tex]
