Answer:
[tex]0[/tex] (no change)
Step-by-step explanation:
Recall that the average rate of change of a function [tex]f(x)[/tex] over the interval [tex][a,b][/tex] is equal to [tex]\frac{f(b)-f(a)}{b-a}[/tex]:
[tex]\frac{h(b)-h(a)}{b-a}\\ \\\frac{h(6)-h(1)}{6-1}\\\\\frac{0-0}{5}\\ \\0[/tex]
Hence, the average rate of change of the function [tex]h(x)[/tex] over the interval [tex][1,6][/tex] is [tex]0[/tex], or no change.
