Answer:
C)
Step-by-step explanation:
If triangle XYZ is equilateral, then its height YW is:
[tex]YW=\sqrt{2^2-1^2} =\sqrt{3}[/tex]
if YW is the diameter of the circle, and diameter = 2 x radius, then
radius = [tex]\dfrac{\sqrt{3} }{2}[/tex]
Area of a circle = [tex]\pi r^2[/tex]
[tex]\implies \textsf{area }=\pi \left(\dfrac{\sqrt{3} }{2}\right)^2=\dfrac34\pi[/tex]
