we know the diameter of it is 2, so its radius must be half that, and the central angle is 5π/3, so
[tex]\textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=1\\ \theta =\frac{5\pi }{3} \end{cases}\implies s=(1)(\frac{5\pi }{3})\implies s\approx 5.24~meters[/tex]
