[tex](a)\\\\\dfrac{d}{dx} \left(e^{x^2 -4x +1} \right)\\\\=e^{x^2 -4x +1} \dfrac{d}{dx} (x^2 -4x +1)\\\\=e^{x^2 -4x +1} (2x -4)\\\\(b)\\\\\dfrac{d}{dx} (2-x \ln x)\\\\=\dfrac{d}{dx} 2 - \dfrac{d}{dx} x \ln x\\\\\\= - \left(x \dfrac{d}{dx} \ln x + \ln x \dfrac{d}{dx} x \right)\\\\\\=-\left( x \cdot \dfrac 1x + \ln x \right)\\\\= - (1 + \ln x)\\\\=-1 -\ln x[/tex]
