Seudónimo Seudónimo
  • 03-01-2017
  • Mathematics
contestada

Solve 3x - 4 ≤ 2 or 2x + 11 ≥ -1. Please help.

Respuesta :

AmplifiedHuman
AmplifiedHuman AmplifiedHuman
  • 03-01-2017
For 3x-4≤2
3x≤6
x≤2

2x+11≥-1
2x≥-12
x≥-6

Hence the solution is 6 ≤x≤2
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austinnevill105
austinnevill105 austinnevill105
  • 03-01-2017
3x -4 is lesser than or equal to 2? okay, see the -4. add it both sides. 3x - 4 (+4) and 2(+ 4) so now you have 3x ≤ 6. divide both sides by 3. So, 3x / 3 is X. 6 divided by 3 is 2. So your answer is X ≤ 2.

2x + 11 
≥ -1. 2x + 11 (-11) ≥ -1 (-11). 2x ≥ -12. 2x / 2 ≥ -12 / 2. Your final answer is X ≥ -6.

You're welcome! :)

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