The value of “k” that will give two real roots is 25/48
Given the equation (1 – 3k) x^2 + 3x – 4, for the equation to have two real roots, this means that b^2 - 4ac > 0
From the given expression
a = 1 - 3k
b = 3
c = -4
Substitute into the equation b^2 - 4ac = 0
3^2 - 4(1 - 3k)(-4) = 0
9 + 16 (1-3k) = 0
9 + 16 - 48k =0
25 = 48k
k = 25/48
Hence the value of “k” that will give two real roots is 25/48
Learn more here: https://brainly.com/question/564715
