jessimejia391 jessimejia391

01-10-2021
Mathematics

contestada

3(k+9)=8-(-3k-19) solution types
a. no solution
b. infinitely many solutions ?

Respuesta :

Аноним Аноним

01-10-2021

hello! your answer would be infinite solutions, or b! hope this helped! ;)

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ayanokoji1710 ayanokoji1710

01-10-2021

Answer:

Step-by-step explanation

3(k+9)=8-(-3k-19)

=> 3k+27=8+3k+19

=>3k+27-8-3k-19=0

=>0=0

so with all value of k, 3(k+9)=8-(-3k-19) always

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