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Answer:
Step-by-step explanation:
Put the argument where the variable is and simplify.
a)
[tex]f(a)=7a+3[/tex]
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b)
[tex]f(a+h)=7(a+h)+3=\boxed{7a+7h+3}[/tex]
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c)
[tex]\dfrac{f(a+h)-f(a)}{h}=\dfrac{(7a+7h+3)-(7a+3)}{h}=\dfrac{7h}{h}\\\\=\boxed{7}[/tex]
