Step-by-step explanation:
[tex] \sqrt{x - 2 + 8} = \sqrt{x + 6} = x[/tex]
[tex] {( \sqrt{x + 6} })^{2} = {x}^{2} [/tex]
[tex]x + 6 = {x}^{2} [/tex]
[tex] {x}^{2} - x - 6 = 0[/tex]
[tex](x - 3)(x + 2) = 0[/tex]
x = 3 or x = -2 we dont use the (-2) because we have a sqrt
So x =3
