Answer: [tex]\large \boldsymbol {\sf x<-5,8 \ \ or \ \ x \in (-\infty \ \ ; \ \ -5,8 ) }[/tex]
Step-by-step explanation:
[tex]\large \boldsymbol {} \sf 3(x+1) < -2(x+13) \\\\ 3x+3<-2x-26 \\\\3x+2x<-26-3 \\\\5x<-29 \\\\x<-5,8 \ \ or \ \ x \in (-\infty \ \ ; \ \ -5,8 )[/tex]
