Answer:
[tex]12a^3d^2-6ad^3[/tex]
To factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5
In the end, the number of times each prime divides the original integer becomes its exponent.
Prime number 2 to the power of 2 equals 4 .
Prime number 3 to the power of 1 equals 3 .
[tex]2^{2} \times 3\times a^{3} \times b^{2} -(2\times3)ad^{3}[/tex]
Result:- [tex]6ad^2\left(2a^2-d\right)[/tex]
OAmalOHopeO
