Answer:
see explanation
Step-by-step explanation:
[tex]\frac{pq+1}{9}[/tex]
= [tex]\frac{(3x+1)(3x-1)+1}{9}[/tex]
= [tex]\frac{9x^2- 1+1}{9}[/tex]
= [tex]\frac{9x^2}{9}[/tex]
= x²
Hello,
[tex]Using\ the\ formula\ (a+b)(a-b)=a^2-b^2\\p=3x+1\\q=3x-1\\\\p*q=(3x+1)*(3x-1)=9x²-1\\\\p*q+1=9x^2\\\\x^2=\dfrac{p*q+1}{9} \\[/tex]
