Answer:
A and D are the answer.
Step-by-step explanation:
We can factor this by grouping
[tex]2 {x}^{2} + 5x - 3[/tex]
[tex]2 {x}^{2} + 6x - x - 3[/tex]
[tex]2x(x + 3) -1 (x + 3)[/tex]
The roots are
[tex](x + 3) = 0[/tex]
and
[tex]2x - 1 = 0[/tex]
Let solve for zero in each roots.
[tex]x = - 3[/tex]
[tex]2x = 1[/tex]
[tex]x = \frac{1}{2} [/tex]
